A thin spherical conducting shell of radius R has a charge q Another charge Q is placed at the centre of the shell The electrostatic potential at point Pwith a distance ofR2 from the centre of the shell is (2024)

FAQs

Is a point charge Q placed at the center of a spherical shell? ›

The correct option is C

The electric potential at the centre of shell will be 14πϵ0 times: Q. A point charge q is placed inside a conducting spherical shell of inner radius 2R and outer radius 3R at a distance of R from the centre of the shell. The electric potential at the centre of shell will be 14πϵ0 times.

the charge q in a sperical region of radius R changes with time t as q=2e^{-3t}. The initial curreng density at the surface of sperical region. Q. The figure shows two conducting concentric sperical shells of radii R and 2R.

A charge q is placed at the centre of the line joining two equal charges Q. The system of the three charges will be in equilibrium if q is equal to : −(Q/2) (Q/4)

A point charge Q is located at the center of the hollow spherical conductor of inner radius R1 and outer radius R2 , the conductor being uncharged initially. The potential at the inner surface will be. KQ[1R1+1R2]

A point charge Q is located at centre of a fixed thin ring of radius R with uniformly distributed charge −Q. The magnitude of the electric field strength at the point lying on the axis of the ring at a distance x from the centre is (x>>R)

A charge 'q' is placed at the centre of a conducting spherical shell of radius R, which is given a charge Q. An external charge Q' is also present at distance R'(R'>R) from 'q'. Then the resultant field will be best represented for region r<R by : [where r is the distance of the point from q]

A sphere of radius R carries charge density proportional to the square of the distance from the center. ρ=Ar2, where A is a positive constant. At a distance of R/2 from the center, the magnitude of the electric field is : Q.

It is uniformly distributed on the surface of the sphere only.

A point charge Q is located on the axis of a disc of radius R at a distance a from the plane of the disc. If one fourth (1/4th) of the flux from the charge passes through the disc, the relation between a and R is a=R√x.

The net charge on hollow conducting spherical shell is zero. If induced charge inside the sphere is negative and to balance, the net charge equals to zero, the outer charge must be equal and opposite of the inside charge.

What happens when a charge is placed inside a spherical shell? ›

Inner charges compensate the center charge which is reflected by same charge on shell outer surface, the shell itself becomes an equipotential surface and external field developes as if only this sphere were charged.

(d) Does the charge Q affect the shell? Yes. Without the charge Q the shell would be neutral.

A charge q is located at the centre of a cube. The electric flux through any face is : πq6(4πε0)

For instance, if you have a solid conducting sphere (e.g., a metal ball) with a net charge Q, all the excess charge lies on the outside. Gauss' law tells us that the electric field inside the sphere is zero, and the electric field outside the sphere is the same as the field from a point charge with a net charge of Q.

If the corner of the cube is taken as the origin, then the flux coming out from the faces of the cube in the direction of X−axis will be- 4πQ. Q/6∈0.

Since there are no charges inside a charged spherical shell . This means the net charge is equal to zero. So magnitude of electric field E=0.

Solution. A charge Q is placed at the centre of a cube. The electric flux through one of its faces is 𝛆 Q 6 ε 0 ̲ . Flux through each face of the cube: As the charge is placed symmetrically to each face of the cube, thus electric flux passing through each face is equal.

Electric field due to induced charges at the centre of sphere is zero. Reason: Electric field at point inside the solid body of conductor is zero.

Answer and Explanation:

If the positive charge (+Q) is located at the center and to maintain the total charge inside the sphere zero, then the induced charge on the inner surface should be negative. Therefore, Q i n n e r = − Q , thus the induced charge on the inner surface of the shell is N (negative).